(26/1+x)+(21/1+x^2)=40

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Solution for (26/1+x)+(21/1+x^2)=40 equation: 


x in (-oo:+oo)

x^2+x+26/1+21/1 = 40 // - 40

x^2+x+26/1+21/1-40 = 0

x^2+x-40+21+26 = 0

x^2+x+7 = 0

DELTA = 1^2-(1*4*7)

DELTA = -27

DELTA < 0

x belongs to the empty set

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